## Example 8.3.4 (e): Function Series Examples

No, unfortunately that theorem does not apply - why not?

In fact, we had to expend quite a lot of energy on technical details to
show that the series converges. If we did divide by
*n ^{2}* instead of

*n*our task would be much simpler, but the resulting function would no longer be linear.

1/n sin(nx)1/n^{2}sin(nx)